1480. Running Sum of 1d Array

Given an array nums. We define a running sum of an array as runningSum[i] = sum(nums[0]…nums[i]).

Return the running sum of nums.

Example 1:

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Input: nums = [1,2,3,4]
Output: [1,3,6,10]
Explanation: Running sum is obtained as follows: [1, 1+2, 1+2+3, 1+2+3+4].

Example 2:

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Input: nums = [1,1,1,1,1]
Output: [1,2,3,4,5]
Explanation: Running sum is obtained as follows: [1, 1+1, 1+1+1, 1+1+1+1, 1+1+1+1+1].

Example 3:

1 2	Input: nums = [3,1,2,10,1] Output: [3,4,6,16,17]

這篇要求array值某位值一直不斷加總前幾位的值，那就給個迴圈，尋訪過程不斷加前一位，學到迴圈用range(len())取得計數。

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